Q 1-When a producer allows 36% commission on the retail price of his product he earns a profit of 8.8 % . What would be his profit percent if the commission is reduced by 24% ?A - 48%B - 48.50%C - 49%D - 49.60%

Answer - D Explanation "Let retail price = Rs. 100, commission. Rs. 36. ∴ S.P. = Rs. (100 - 36) = Rs. 64 But , profit = 8.8 % ∴ C.P. = Rs. ([100/108.8]×64)=Rs.1000/17 New commission = Rs.12. New S.P. = Rs. (100 - 12)= Rs. 88 Gain = Rs. (88−[1000/17]) =Rs. 496/17 ∴ Gain % = ([496/17]×[17/1000]x100)% = 49.6% "Q 2-At what percentage above the C.P. must an article be marked so as to gain 33 after allowing a customer a discount of 5%?A - 40%B - 42%C - 44%D - 45%

Answer - A Explanation "Let C.P. = Rs. 100, Then S.P.. = Rs. 133 Let marked price be Re. x Then 95% of x = 133 ⇒ 95x/100 =133 ⇒ x=(133×100/95) ⇒140. ∴ Marked price = 40 % above C.P. "Q 3-A retailer buys 40 pens at the marked price of 36 pens from a wholesaler . If he sells these pens giving a discount of 1% , what is the profit percent ?A - 8%B - 9%C - 10%D - 11%

Answer - C Explanation "Let the marked price of each pen be Re.1 Then ,C.P. of 40 pens = Rs. 36. S.P. of 40 pens = 99% of Rs. 40 = 39.60 ∴ profit % = ([3.60/36]×100)% = 10%"Q 4-"An uneducated retailer marks all his goods at 50% above the cost price and thinking that he will still make 25% profit offers a discount of 25% on the marked price . What is his actual profit on the sales ?"A - 12.50%B - 12.75%C - 13%D - 13.50%

Answer - A Explanation "Let C.P. = Rs. 100. Then,marked price = Rs. 150. S.P. = 75% of Rs. 150 = Rs. 112.50 ∴∴ Gain % = 12.50%"Q 5-After getting two successive discount, a shirt with a list price of Rs. 150 is available at Rs. 105. If the second discount is 12.5% , find the first discount .A - 20%B - 22%C - 24%D - 25%

Answer - A Explanation "Let the first discount be x% Then , 97.5% of (100 - x)% of 150 = 105 ⇒ [(87.5/100)×((100−x)/100)×150= 105 ⇒ 100−x =(105×100×100)/(150×87.5) ⇒ x= (100−80) =20. ∴ First discount = 20% "Q 6-Find the single discount equivalent to a series discount of 20% , 10% and 5% .A - 30%B - 30.50%C - 31%D - 31.60%

Answer - D Explanation "Let marked price be Rs. 100 Then , Net S.P. = 95% pf 90% of 80% of Rs. 100 = Rs. (95/100)×(90/100)×(80/100)×100)= Rs. 68.40 ∴ Required discount = (100 - 68.40)% = 31.6% "Q 7-A man bought a horse and a carriage for Rs. 3000. He sold the horse at a gain of 20% and the carriage at a loss of 10% , there by gaining 2% on the whole . Find the cost of the horse.A - Rs. 1200B - Rs. 1250C - Rs. 1275D - Rs. 1300

Answer - A Explanation "Let the C.P. of the horse be Rs. Then ,C.P. of the carriage = Rs. (3000 - x) ∴ 20% of x - 10% of (3000 - x) = 2% of 3000 ⇒ (x/5)−[(3000−x)/10] ⇒ 2x−3000+x= 600 ⇒ 3x = 3600 ⇒ 3x = 3600 ⇒ x = 1200 Hence , C.P. of the horse = Rs. 1200. "Q 8-A dealer sold three-fourth of his articles at a gain of 20% and the remaining at cost price . Find the gain earned by him in the whole transaction .A - 13%B - 14%C - 15%D - 16%

Answer - C Explanation "Let C. P.of whole be Rs. X C.P. of 33/4th = Rs 3x/4,. C.P. of 1/4 th = Rs. x/4 ∴ Total S.P. = Rs[(120 %of 3x/4)+x/4] =Rs.((9x/10)+(x/4))=Rs.23x/20 Gain = Rs. ((23x/20)−x)=Rs.3x/20 ∴ Gain % = ((3x/20)×(1/x)×100) = 15% "Q 9-The price of a jewel ,passing through three hands, rises on the whole by 65 % .If the first and the second sellers earned 20% and 25% profit respectively, find the percentage profit earned by the third seller.A - 8 %B - 9 %C - 10 %D - 11 %

Answer - C Explanation "Let the original price of the jewel be Rs. P and let the profit earned by the third seller be x% Then ,(100 + x)% of 125% of 120% of P = 165% of P ⇒ [(100+x)/100×(125/100)×(120/100)×P]⇒ ((165/100)×P) ⇒(100+x)=((165×100×100)/(125×120)=110 ⇒ x= 10% "Q 10-A man sells an article at a profit of 25% . If he had bought it at 20% less and sold i for Rs. 10.50 less , he would have gained 30% ,Find the cost price of the article .A - Rs. 45B - Rs. 50C - Rs. 55D - Rs. 60

Answer - B Explanation "Let he C.P. be Rs. x 1st S.P. = 125% of x=125x/100= 5x/4; 2nd S.P. = 80% of x= 80x/100= 4x/5. 2nd S.P. = 130% of 4x/5 = (130/100×(4x/5))=26x/25 ∴ (5x/4) −(26x/25) =10.50 ⇔ x= (10.50×(100/21)) = 50 Hence , C.P. = Rs. 50. "Q 11-A tradesman sold an article at a loss of 20% . If he selling price had been increased by Rs. 100 , there would have been a gain of 5% . what was the cost price of the article ?A - Rs. 350B - Rs. 380C - Rs. 400D - Rs. 430

Answer - C Explanation "Let C.P. be Rs. x . Then , (105% of x) - (80% of x) = 100 or 25% of x= 100 ∴ x/4=100 or x=400 So , C.P. = Rs. 400."Q 12-"An article is sold at a certain price . By selling it at 2/3 of that price one loses 10% . Find the gain percent at original price ."A - 35%B - 36%C - 37%D - 38%

Answer - A Explanation "Let the original S.P. be Rs. x Then , New S.P. = Rs. 2x/3, loss = 10% So , C.P. = Rs. ((100/90)×(2x/3))=20x/27 Now , C.P. = Rs. 20x/27,S.P.=Rs. x , gain = Rs.(x−(20x/27))=Rs. 7x/27 ∴ Gain % = ((7x/27)×(27/20x)×100)% = 35% "Q 13-"Monika purchased a pressure cooker at 9/10th of its selling price and sold it at 8% more than its S.P. . Find her gain percent ."A - 18%B - 19%C - C. 20%D - D. 21%

Answer - C Explanation "Let the S.P. be Rs. x, Then ,C.P. = Rs. 9x/10 Receipt = 108% of Rs. x=Rs.27x/25 Gain = Rs. ((27x/25)−(9x/10)) =Rs.((108x−90x)/100) = Rs.18x/100 ∴ Gain % = ((18x/100)×(10/9x)×100)% = 20%."Q 14-If the manufacturer gains 10% , the wholesale dealer 15% and the retailer 25% , then find the cost of production of a table , the retail price of which is Rs. 1265 ?A - Rs. 800B - B. Rs. 825C - C. Rs. 850D - D. Rs. 900

Answer - A Explanation "Let the cost of production of the table be Rs. x Then , 125% of 115% of 110% of x = 1265. ⇒ (125/100) × (115/100) × (110/100) × x = 1265 ⇒ 253x/160= 1265 ⇒ x = ((1265×160)/253) = Rs. 800. "Q 15-A dishonest dealer professes to sell his goods at cost price but uses a weight of 960 gm for a g. weight . Find his gain percent .A - 4B - 13/3C - 25/6D - 9/2

Answer - C Explanation Gain % = [Error/[(TrueValue)−(Error)]×100]= ([40/960]×100)%= %= 25/6%