Q 1-3889 + 12.925 - ? = 3854.002

A - 47.095

B - 47.72

C - 47.932

D - 47.95

```Answer - D

Explanation

"Let 3889 + 12.92 -x= 384.002 = 3854.002

Then x = (3889 + 12.952) -3854.002

= 3901.952 - 3854.002 = 47.95"
```

Q 2-What decimal of an hour is a second ?

A - 0.0025

B - 0.0256

C - 0.00027

D - 0.000126

```Answer - C

Explanation

Required decimal =1/(60*60)=1/3600= .00027
```

Q 2-What decimal of an hour is a second ?

A - 0.0025

B - 0.0256

C - 0.00027

D - 0.000126

```Answer - C

Explanation

Required decimal =1/(60*60)=1/3600= .00027
```

Q 3-The value of(0.96)³ - (0.1)³/(0.96)² + 0.096 + (0.1)² is

A - 0.86

B - 0.95

C - 0.97

D - 1.06

```Answer - A

Explanation

"Given expression = (0.96)³-(0.1)³/(0.96)2+(0.96*0.1)+(0.1)2
=(a³-b³) / a²+(ab+b²)
=(a-b)
=(0.96-0.1)
=(0.86)"
```

Q 4-The Value of 0.1*0.1*0.1+0.02*0.02*0.02/0.20.20.2+0.04*0.04*0.04 is:

A - 0.0125

B - 0.125

C - 0.25

D - 0.5

```Answer - B

Explanation

Given expression=(0.1)³+(0.02)³/23[(0.1)³+(0.023)]=1/8=0.125
```

Q 5-If 2994 ÷ 14.5 = 172, then 29.94 ÷ 1.45 = ?

A - 0.172

B - 1.72

C - 17.2

D - 172

```Answer - C

Explanation

"29.94/1.45=299.4/14.5 =(2994/14.5*1/10)

[here ,substitute 172 in the place of 2994/14.5]

=172/10 187.2"
```

Q 6-When 0.232323..... is converted into a fraction, then the result is:

A - 1 5

B - 2 9

C - 23 99

D - 23 100

```Answer - C

Explanation

0.232323....=0.23=23/99
```

Q 7-.009/?=.01

A - 0.0009

B - 0.09

C - 0.9

D - 9

```Answer - C

Explanation

"Let .009/x=.01
Then x=.009/.01=9/1=.9"
```

Q 8-The expression (11.98 x 11.98 + 11.98 x x + 0.02 x 0.02) will be a perfect square for x equal to:

A - 0.02

B - 0.2

C - 0.04

D - 0.4

```Answer - C

Explanation

"Given expression = (11.98)² + (0.02)² + 11.98 * x.
For the given expression to be a perfect square,
we must have 11.98 * x = 2 x 11.98 x 0.02 or x = 0.04"
```

Q 9-(0.1667)(0.8333)(0.3333)/ (0.2222)(0.6667)(0.1250) is approximately equal to:

A - 2

B - 2.4

C - 2.43

D - 2.5

```Answer - D

Explanation

"Given expression
= [(0.333)/(0.2222)] X [(0.1667)(0.833) / (0.6667)(0.1250)]
= 3333/2222 X ([1/6 X 5/6] / [2/3 X 125/1000])
= [3/2 X 1/6 X 5/6 X 3/2 X 8] = 5/2 =2.50"
```

Q 10-3990 + 12.959 - ? = 3954.002

A - 47.095

B - 47.752

C - 47.932

D - 48.95

```Answer - D

Explanation

"Let 3990 + 12.952 - x = 3854.002.

Then x = (3990 + 12.952) - 3854.002

= 4002.959 - 3854.002

= 48.95.
"
```

Q 11-0.04 x 0.0162 is equal to:

A - 6.48 x 10-3

B - 6.48 x 10-4

C - 6.48 x 10-5

D - 6.48 x 10-6

```Answer - B

Explanation

"4 x 162 = 648. Sum of decimal places = 6.

So, 0.04 x 0.0162 = 0.000648 = 6.48 x 10^(-4 )"
```

Q 12-4.2 x 4.2 - 1.9 x 1.9 / 2.3 x 6.1 is equal to:

A - 0.5

B - 1

C - 20

D - 22

```Answer - B

Explanation

"Given expression:
a² - b² /(a + b)(a - b)
= (a² - b² ) (a² - b² )=1"
```

Q 13-If 144/0.144=14.4/x then the value of x is

A - 0.0144

B - 1.44

C - 14.4

D - 144

```Answer - A

Explanation

"
 / [0.144]=14.34/x
=>[144*1000]/144=[14.4]/x
=>x=[14.4/1000]=0.0144
"
```

Q 14-The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?

A - 2010

B - 2011

C - 2012

D - 2013

```Answer - B

Explanation

"Suppose commodity X will cost 40 paise
more than Y after z years.

Then,
(4.20 + 0.40z) - (6.30 + 0.15z) = 0.40 + 0.25z
= [0.40 + 2.10] x [2.50/0.25]=250/25
=10 X will cost 40 paise more
than Y 10 years after 2001 i.e., 2011."
```

Q 15-892.7 - 573.07 - 95.007 = ?

A - 224.623

B - 224.777

C - 233.523

D - 414.637

```Answer - A

Explanation

"Given expression
= 8927 - (573.07 + 95.007)
= 8927 - 668.077 = 224.623."
```